File:Fse-ideal-gas-law-v3.svg

Fse-ideal-gas-law-v3.svg (SVG file, nominally 900 × 600 pixels, file size: 7 KB)

Summary

Buoyancy in a fire room with one opening: the pressure difference between inside and outside grows with height above the neutral plane, where it is zero. Based on Van Rossum (2027), §3.2, and Klote (2002), p. 4-276.

Original vector illustration for Ideal gas law, level 2 Intermediate.

Source basis: Van Rossum (2027), §3.2 (Δp ≈ g·h·(ρ₁ − ρ₂), neutral plane, inflow below, outflow above); Klote (2002), p. 4-276 (buoyancy pressure, 13 Pa example)
Alt text: Fire room with a door: smoke out above the neutral plane, air in below; a graph shows the pressure difference growing with height.

Licensing

New drawing by Fire Safety Academy. © Fire Safety Academy.

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	Date/Time	Thumbnail	Dimensions	User	Comment
current	17:02, 2 November 2026		900 × 600 (7 KB)	Lisa (talk \| contribs)	Watermark: Fire Safety Academy logo icon, 70 px, 45 % opacity

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Ideal gas law

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Short title	Buoyancy in a fire room with one opening: the pressure difference between inside and outside grows with height above the neutral plane, where it is zero. Based on Van Rossum (2027), §3.2, and Klote (2002), p. 4-276.
Image title	Fire room with a door: smoke out above the neutral plane, air in below; a graph shows the pressure difference growing with height. Source basis: Van Rossum (2027), §3.2 (Δp ≈ g·h·(ρ₁ − ρ₂), neutral plane, inflow below, outflow above); Klote (2002), p. 4-276 (buoyancy pressure, 13 Pa example)
Width	900
Height	600